Python: zip() function
zip() function
The zip() function is used to make an iterator that aggregates elements from each of the iterables. The iterator stops when the shortest input iterable is exhausted. With a single iterable argument, it returns an iterator of 1-tuples. With no arguments, it returns an empty iterator.
Version:
(Python 3.2.5)
Syntax:
zip(*iterables)
Parameter:
Name | Description | Required / Optional |
---|---|---|
*iterables | Iterator objects that will be joined together. | Required |
Return value:
Returns an iterator of tuples, where the i-th tuple contains the i-th element from each of the argument sequences or iterables.
Example: Python zip() function
x = [1, 2, 3]
y = [4, 5, 6]
zipped = zip(x, y)
print(list(zipped))
Output:
[(1, 4), (2, 5), (3, 6)]
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Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
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