SQL SQRT() function
SQRT() function
SQL SQRT() returns the square root of a given value in the argument.
Syntax:
SQRT( expression )
Parameters:
Name | Description |
---|---|
expression | An expression which is a numeric value or numeric data type. |
MySQL, PostgreSQL, SQL Server, and Oracle
All of above platforms support the SQL syntax of SQRT().
SQL SQRT() function: Pictorial presentation
Example :
To get the square root of 36 from the DUAL table, the following SQL statement can be used:
SELECT SQRT(36)
FROM dual;
Output:
SQRT(36) ---------- 6
SQL SQRT() function with distinct
Sample table: customer
To get the unique square root of 'opening_amt' from 'customer' table, the following SQL statement can be used :
SELECT SQRT(opening_amt)
FROM customer;
Output:
SQRT(OPENING_AMT) ----------------- 77.4596669 54.7722558 70.7106781 70.7106781 63.2455532 77.4596669 70.7106781 83.6660027 83.6660027 89.4427191 83.6660027 83.6660027 83.6660027 70.7106781 63.2455532 100 77.4596669 89.4427191 70.7106781 83.6660027 89.4427191 89.4427191 89.4427191 89.4427191 83.6660027
Note: Outputs of the said SQL statement shown here is taken by using Oracle Database 10g Express Edition.
Here is a slide presentation which covers the SQL arithmetic functions.
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SQL: Tips of the Day
SQL Server SELECT into existing table.
INSERT INTO dbo.TABLETWO SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:
INSERT INTO dbo.TABLETWO (col1, col2) SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
Database: SQL Server
Ref: https://bit.ly/3y6tpA3
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