C Exercises: Check whether a given number is a Kaprekar number or not
C Numbers: Exercise-6 with Solution
Write a program in C to check whether a given number is a Kaprekar number or not.
Test Data
Input a number: 45
Sample Solution:
C Code:
# include <stdio.h>
# include <stdbool.h>
# include <math.h>
bool chkkaprekar(int n)
{
if (n == 1)
return true;
int sqr_n = n * n;
int ctr_digits = 0;
while (sqr_n)
{
ctr_digits++;
sqr_n /= 10;
}
sqr_n = n*n;
for (int r_digits=1; r_digits<ctr_digits; r_digits++)
{
int eq_parts = pow(10, r_digits);
if (eq_parts == n)
continue;
int sum = sqr_n/eq_parts + sqr_n % eq_parts;
if (sum == n)
return true;
}
return false;
}
int main()
{
int kpno;
printf("\n\n Check whether a given number is a Kaprekar number: \n");
printf(" -------------------------------------------------------\n");
printf(" Input a number: ");
scanf("%d",&kpno);
if (chkkaprekar(kpno)==true)
{
printf("%d is a Kaprekar number. \n",kpno);
}
else
{
printf("%d is not a Kaprekar number. \n",kpno);
}
}
Sample Output:
Input a number: 45 45 is a Kaprekar number.
Pictorial Presentation:
Flowchart:
C Programming Code Editor:
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Previous: Write a program in C to find the Deficient numbers (integers) between 1 to 100.
Next: Write a program in C to generate and show all Kaprekar numbers less than 1000.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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