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C Exercises: Find the Deficient numbers (integers) between 1 to 100

C Numbers: Exercise-5 with Solution

Write a program in C to find the Deficient numbers (integers) between 1 to 100.

Sample Solution:

C Code:

# include <stdio.h>
# include <stdbool.h>
# include <math.h>

int getSum(int n)
{
    int sum = 0;
    for (int i=1; i<=sqrt(n); i++)
    {
        if (n%i==0)
        {
            if (n/i == i)
                sum = sum + i;
            else 
            {
                sum = sum + i;
                sum = sum + (n / i);
            }
        }
    }
    sum = sum - n;
    return sum;
}
bool checkDeficient(int n)
{
    return (getSum(n) < n);
}
int main()
{
int n,ctr=0;
  printf("\n\n The Deficient numbers between 1 to 100 are: \n");
  printf(" ------------------------------------------------\n");
for(int j=1;j<=100;j++)
{
    n=j;
    if(checkDeficient(n)==true)
    {
        printf("%d ",n);
        ctr++;
        
    }
}
printf("\n The Total number of Deficient numbers are: %d \n",ctr);
}

Sample Output: 

The Deficient numbers between 1 to 100 are:                                                                  
 ------------------------------------------------                                                             
1 2 3 4 5 7 8 9 10 11 13 14 15 16 17 19 21 22 23 25 26 27...

Pictorial Presentation:

C programming: Find the Deficient numbers (integers) between 1 to 100.

Flowchart:

Flowchart: Find the Deficient numbers (integers) between 1 to 100

C Programming Code Editor:

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP