C Exercises: Array fill, replace each subsequent position of the array by one-third value of the previous

C Basic Declarations and Expressions: Exercise-129 with Solution

Write a C program that reads an array (length 10), and replace the first element of the array by a give number and replace each subsequent position of the array by one-third value of the previous.

Sample Solution:

C Code:

#include <stdio.h>
int main ()
{
  int i;
  double array_nums[10];
  double n;
  printf("Input a number:\n");
  scanf("%lf", &n);
  array_nums[0] = n;
  for (i = 1; i < 10; i++)
  {
    n = n/3;
    array_nums[i] = n;

  }
  printf("\nArray elements:\n");
  for (i = 0; i < 10; i++)
  {

    printf("array_nums[%d] = %.4lf\n", i, array_nums[i]);

  }
}

Sample Output:

Input a number:
35

Array elements:
array_nums[0] = 35.0000
array_nums[1] = 11.6667
array_nums[2] = 3.8889
array_nums[3] = 1.2963
array_nums[4] = 0.4321
array_nums[5] = 0.1440
array_nums[6] = 0.0480
array_nums[7] = 0.0160
array_nums[8] = 0.0053
array_nums[9] = 0.0018

Flowchart:

C programming Code Editor:

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