C Exercises: Fill the array elements with number o to n – 1 repeated times
C Basic Declarations and Expressions: Exercise-128 with Solution
Write a C program that reads an array of integers (length 10), fill the array elements with number o to a (given number) n – 1 repeated times where 2 <= n <= 10.
Sample Solution:
C Code:
#include <stdio.h>
int main ()
{
int n, i, array_nums[10], k;
printf("Input an integer (2-10)\n");
scanf("%d", &n);
if (n>=2 && n<=10)
{
k = 0;
for (i = 0; i < 10; i++)
{
array_nums[i] = k;
k++;
if (k == n)
{
k = 0;
}
}
for (i = 0; i < 10; i++)
{
printf("array_nums[%d] = %d\n", i, array_nums[i]);
}
}
}
Sample Output:
Input an integer (2-10) 8 array_nums[0] = 0 array_nums[1] = 1 array_nums[2] = 2 array_nums[3] = 3 array_nums[4] = 4 array_nums[5] = 5 array_nums[6] = 6 array_nums[7] = 7 array_nums[8] = 0 array_nums[9] = 1
Flowchart:
C programming Code Editor:
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Previous: Write a C program that reads an array of integers (length 8), replace the 1st element by the 8th, 2nd by the 7th and so on. Print the final array.
Next: Write a C program that reads an array (length 10), and replace the first element of the array by a give number and replace each subsequent position of the array by one-third value of the previous.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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