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C Exercises: Fill the array elements with number o to n – 1 repeated times

C Basic Declarations and Expressions: Exercise-128 with Solution

Write a C program that reads an array of integers (length 10), fill the array elements with number o to a (given number) n – 1 repeated times where 2 <= n <= 10.

Sample Solution:

C Code:

#include <stdio.h>
int main ()
{
  int n, i, array_nums[10], k;
  printf("Input an integer (2-10)\n");
  scanf("%d", &n);

  if (n>=2 && n<=10)
  {
  k = 0;

  for (i = 0; i < 10; i++)
  {

    array_nums[i] = k;
    k++;

    if (k == n)
    {

      k = 0;

    }
  }
  for (i = 0; i < 10; i++)
  {

    printf("array_nums[%d] = %d\n", i, array_nums[i]);

  }
}
}

Sample Output:

Input an integer (2-10)
8
array_nums[0] = 0
array_nums[1] = 1
array_nums[2] = 2
array_nums[3] = 3
array_nums[4] = 4
array_nums[5] = 5
array_nums[6] = 6
array_nums[7] = 7
array_nums[8] = 0
array_nums[9] = 1

Flowchart:

C Programming Flowchart: Fill the array elements with number o to n – 1 repeated times.

C programming Code Editor:

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Next: Write a C program that reads an array (length 10), and replace the first element of the array by a give number and replace each subsequent position of the array by one-third value of the previous.

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP