C Exercises: Change the array elements
C Basic Declarations and Expressions: Exercise-127 with Solution
Write a C program that reads an array of integers (length 8), replace the 1st element by the 8th, 2nd by the 7th and so on. Print the final array.
Sample Solution:
C Code:
#include <stdio.h>
int main ()
{
unsigned short i, j;
short array_nums[8], n, temp1, temp2;
printf("Input 8 array elements:\n");
for (i = 0; i < 8; i++)
{
scanf("%hd", &n);
array_nums[i] = n;
}
for (i = 0, j = 7; i <= 4 && j >= 4; i++, j--)
{
temp1 = array_nums[i];
temp2 = array_nums[j];
array_nums[i] = temp2;
array_nums[j] = temp1;
}
printf("\nModified array:\n");
for (i = 0; i < 8; i++)
printf("array_nums[%d] = %d\n", i, array_nums[i]);
}
Sample Output:
Input 8 array elements: 25 35 17 -5 29 45 60 65 Modified array: array_nums[0] = 65 array_nums[1] = 60 array_nums[2] = 45 array_nums[3] = 29 array_nums[4] = -5 array_nums[5] = 17 array_nums[6] = 35 array_nums[7] = 25
Flowchart:
C programming Code Editor:
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Previous: Write a C program that reads an array (length 7) and print all array positions that store a value less or equal to 0.
Next: Write a C program that reads an array of integers (length 10), fill the array elements with number o to a (given number) n – 1 repeated times where 2 <= n <=10.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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