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C Exercises: Accept an integer and print next ten consecutive odd and even numbers

C Basic Declarations and Expressions: Exercise-107 with Solution

Write a C program that accepts an integer and print next ten consecutive odd and even numbers.

Sample Solution:

C Code:

#include <stdio.h>
int main () {
  int a, i, ctr = 0;
  printf("Input an integer number:\n");
  scanf("%d", &a);

  printf("\nNext 10 consecutive odd numbers:\n");
  for (i = a+1; ctr < 10; i++){

    if (i % 2 != 0){

      printf("%d, ", i);
      ctr++;
      
    }
  }
  printf("\n\nNext 10 consecutive even numbers:\n");
  ctr=0;
  for (i = a+1; ctr < 10; i++){

    if (i % 2 == 0){

      printf("%d, ", i);
      ctr++;
      
    }
  }
}

Sample Output:

Input an integer number:
15

Next 10 consecutive odd numbers:
17, 19, 21, 23, 25, 27, 29, 31, 33, 35,

Next 10 consecutive even numbers:
26, 28, 30, 32, 34, 36, 38, 40, 42, 44,

Flowchart:

C Programming Flowchart: Accept an integer and print next ten consecutive odd and even numbers.

C programming Code Editor:

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Next: Write a C program that reads two integer values and calculate the sum of all odd and values between them.

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP