C Exercises: Sum of all odd, even values between two integers

C Basic Declarations and Expressions: Exercise-108 with Solution

Write a C program that reads two integer values and calculate the sum of all odd and values between them.

Sample Solution:

C Code:

#include <stdio.h>
int main () {
  int a, b, i, ctr = 0, sum_odd = 0, sum_even = 0;
  printf("Input the first integer number:\n");
  scanf("%d", &a);
  printf("Input the second integer number (greater than first integer):\n");
  scanf("%d", &b);
  
  if (b>a)
  {
    for (i = a; i <= b; i++){

    if (i % 2 != 0){      
      sum_odd = sum_odd + i;
    }
  }
  printf("Sum of all odd values between %d and %d:", a, b);
  printf("\n%d", sum_odd);
  ctr=0;
   
   for (i = a; i <= b; i++){
    if (i % 2 == 0){
       sum_even = sum_even + i;
    }
  }
  printf("\nSum of all even values between %d and %d:", a, b);
  printf("\n%d", sum_even);
}
}

Sample Output:

Input the first integer number:
25
Input the second integer number (greater than first integer):
45
Sum of all odd values between 25 and 45:
385
Sum of all even values between 25 and 45:
350

Flowchart:

C programming Code Editor:

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