C Exercises: Accept 7 integer values and count the even, odd, positive and negative values

C Basic Declarations and Expressions: Exercise-106 with Solution

Write a C program that accepts 7 integer values and count the even, odd, positive and negative values.

Sample Solution:

C Code:

#include <stdio.h>
int main () 
{

int x, i, ctr_even = 0, ctr_odd = 0, ctr_positive = 0, ctr_negative = 0;
printf("\nInput 7 integers:\n");
for (i = 0; i < 7; i++){

  scanf("%d", &x);
  if (x > 0){

    ctr_positive++;

  }
  if (x < 0){

    ctr_negative++;

  }
  if (x % 2 == 0){

    ctr_even++;

  }
  if (x % 2 != 0){

    ctr_odd++;

  }
}

printf("\nNumber of even values: %d", ctr_even);
printf("\nNumber of odd values: %d", ctr_odd);
printf("\nNumber of positive values: %d", ctr_positive);
printf("\nNumber of negative values: %d", ctr_negative);
}

Sample Output:

Input 7 integers:
10
12
15
-15
26
35
17

Number of even values: 3
Number of odd values: 4
Number of positive values: 6
Number of negative values: 1

Flowchart:

C programming Code Editor:

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