C Exercises: Shift an element in left direction and return a new array

C-programming basic algorithm: Exercise-68 with Solution

Write a C program to shift an element in left direction and return a new array.

C Code:

#include <stdio.h>
#include <stdlib.h>
int main(void){ 
    int arr_size;
    int a1[] = {10, 20, 30, 40};
    arr_size = sizeof(a1)/sizeof(a1[0]);
    printf("Elements in original array are: ");  
    print_array(a1, arr_size);
    int result[arr_size];
    for (int i = 0; i < arr_size; i++)
         {
           result[i] = a1[(i + 1) % arr_size];
         }
    printf("\nElements in new array are: ");  
    print_array(result, arr_size);
    }         
 print_array(int parray[], int size)
  {
   int i;      
   for( i=0; i<size-1; i++)  
    {  
        printf("%d, ", parray[i]);  
    } 
   printf("%d ", parray[i]);  
   printf("\n");   
  }

Sample Output:

Elements in original array are: 10, 20, 30, 40 

Elements in new array are: 20, 30, 40, 10

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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