C Exercises: Create a new array taking the elements before the element value 5 from a given array of integers
C-programming basic algorithm: Exercise-69 with Solution
Write a C program to create a new array taking the elements before the element value 5 from a given array of integers.
C Code:
#include <stdio.h>
#include <stdlib.h>
int main(void){
int arr_size;
int a1[] = {1, 2, 3, 5, 7};
arr_size = sizeof(a1)/sizeof(a1[0]);
printf("Elements in original array are: ");
print_array(a1, arr_size);
int size = 0;
int pre_ele_5[arr_size];
for (int i = 0; i < arr_size; i++)
{
if (a1[i] == 5)
{
size = i;
break;
}
}
int result[size];
for (int j = 0; j < size; j++)
{
result[j] = a1[j];
}
arr_size = sizeof(result)/sizeof(result[0]);
printf("\nElements in new array are: ");
print_array(result, arr_size);
}
print_array(int parray[], int size)
{
int i;
for( i=0; i<size-1; i++)
{
printf("%d, ", parray[i]);
}
printf("%d ", parray[i]);
printf("\n");
}
Sample Output:
Elements in original array are: 1, 2, 3, 5, 7 Elements in new array are: 1, 2, 3
Pictorial Presentation:
Flowchart:
C Programming Code Editor:
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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