C Exercises: Check a given array of integers and return true if the array contains three increasing adjacent numbers
C-programming basic algorithm: Exercise-67 with Solution
Write a C program to check a given array of integers and return true if the array contains three increasing adjacent numbers.
C Code:
#include <stdio.h>
#include <stdlib.h>
int main(void){
int arr_size;
int array1[] = {1, 2, 3, 5, 3, 7};
arr_size = sizeof(array1)/sizeof(array1[0]);
printf("%d",test(array1, arr_size));
int array2[] = {3, 7, 5, 5, 3, 7 };
arr_size = sizeof(array2)/sizeof(array2[0]);
printf("\n%d",test(array2, arr_size));
int array3[] = { 3, 7, 5, 5, 6, 7, 5};
arr_size = sizeof(array3)/sizeof(array3[0]);
printf("\n%d",test(array3, arr_size));
}
int test(int numbers[], int arr_size)
{
for (int i = 0; i <= arr_size - 3; i++)
{
if (numbers[i] == numbers[i + 1] - 1
&& numbers[i] == numbers[i + 2] - 2)
{
return 1;
}
}
return 0;
}
Sample Output:
1 0 1
Pictorial Presentation:
Flowchart:
C Programming Code Editor:
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Previous: Write a C program to check a given array of integers and return true if the specified number of same elements appears at the start and end of the given array.
Next: Write a C program to shift an element in left direction and return a new array.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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