SQL Exercises: Make a list in ascending order for all customers who holds a grade less than 300 and works either through a salesman or by own

SQL JOINS: Exercise-9 with Solution

From the following tables write a SQL query to find those customers with a grade less than 300. Return cust_name, customer city, grade, Salesman, salesmancity. The result should be ordered by ascending customer_id.

Sample table: customer

Sample table: salesman

Sample Solution:

SELECT a.cust_name,a.city,a.grade, 
b.name AS "Salesman", b.city 
FROM customer a 
LEFT OUTER JOIN salesman b 
ON a.salesman_id=b.salesman_id 
WHERE a.grade<300 
ORDER BY a.customer_id;

Output of the Query:

cust_name	city		grade	Salesman	city
Nick Rimando	New York	100	James Hoog	New York
Jozy Altidor	Moscow		200	Paul Adam	Rome
Graham Zusi	California	200	Nail Knite	Paris
Brad Davis	New York	200	James Hoog	New York
Geoff Cameron	Berlin		100	Lauson Hen	San Jose

Explanation:

Pictorial presentation:

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Query Visualization:

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Previous: From the following tables write a SQL query to display the cust_name, customer city, grade, Salesman, salesman city. The result should be ordered by ascending on customer_id.
Next: Write a SQL statement to make a report with customer name, city, order number, order date, and order amount in ascending order according to the order date to find that either any of the existing customers have placed no order or placed one or more orders.