SQL Exercises: Make a report with customer name, city, order number, date, and amount in ascending order on order date to find either any of the existing customer have placed no order or placed one or more orders

SQL JOINS: Exercise-10 with Solution

Write a SQL statement to make a report with customer name, city, order number, order date, and order amount in ascending order according to the order date to determine whether any of the existing customers have placed an order or not.

Sample table: orders

Sample table: customer

Sample Solution:

SELECT a.cust_name,a.city, b.ord_no,
b.ord_date,b.purch_amt AS "Order Amount" 
FROM customer a 
LEFT OUTER JOIN orders b 
ON a.customer_id=b.customer_id 
order by b.ord_date;

Output of the Query:

cust_name	city		ord_no	ord_date	Order Amount
Nick Rimando	New York	70013	2012-04-25	3045.60
Julian Green	London		70012	2012-06-27	250.45
Brad Davis	New York	70005	2012-07-27	2400.60
Jozy Altidor	Moscow		70011	2012-08-17	75.29
Geoff Cameron	Berlin		70004	2012-08-17	110.50
Brad Guzan	London		70009	2012-09-10	270.65
Nick Rimando	New York	70008	2012-09-10	5760.00
Graham Zusi	California	70007	2012-09-10	948.50
Graham Zusi	California	70001	2012-10-05	150.50
Nick Rimando	New York	70002	2012-10-05	65.26
Fabian Johnson	Paris		70010	2012-10-10	1983.43
Geoff Cameron	Berlin		70003	2012-10-10	2480.40

Explanation:

Pictorial presentation:

Practice Online

Query Visualization:

Duration:

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Cost:

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Previous: From the following tables write a SQL query to find those customers whose grade less than 300. Return cust_name, customer city, grade, Salesman, saleman city. The result should be ordered by ascending customer_id.
Next: Write a SQL statement to make a report with customer name, city, order number, order date, order amount salesman name and commission to find that either any of the existing customers have placed no order or placed one or more orders by their salesman or by own.