Python: Find the dictionary key whose case is different than all other keys
Python Programming Puzzles: Exercise-62 with Solution
Write a Python program to find the dictionary key whose case is different than all other keys.
Input: {'red': '', 'GREEN': '', 'blue': 'orange'} Output: GREEN Input: {'RED': '', 'GREEN': '', 'orange': '#125GD'} Output: orange
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Sample Solution:
Python Code:
#License: https://bit.ly/3oLErEI
def test(dict_data):
for different in dict_data:
if all(k.islower() != different.islower() for k in dict_data if k != different):
return different
dict_data = {"red": "", "GREEN": "", "blue": "orange"}
print("Original dictionary key-values:")
print(dict_data)
print("Find the dictionary key whose case is different than all other keys:")
print(test(dict_data))
dict_data = {"RED": "", "GREEN": "", "orange": "#125GD"}
print("\nOriginal dictionary key-values:")
print(dict_data)
print("Find the dictionary key whose case is different than all other keys:")
print(test(dict_data))
Sample Output:
Original dictionary key-values: {'red': '', 'GREEN': '', 'blue': 'orange'} Find the dictionary key whose case is different than all other keys: GREEN Original dictionary key-values: {'RED': '', 'GREEN': '', 'orange': '#125GD'} Find the dictionary key whose case is different than all other keys: orange
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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