Python: Find the number of stones in each pile

Python Programming Puzzles: Exercise-4 with Solution

We are making n stone piles! The first pile has n stones. If n is even, then all piles have an even number of stones. If n is odd, all piles have an odd number of stones. Each pile must more stones than the previous pile but as few as possible. Write a Python program to find the number of stones in each pile.

Input:  2
Output:
[2, 4]

Input:  10
Output:
[10, 12, 14, 16, 18, 20, 22, 24, 26, 28]

Input: 3
Output:
[3, 5, 7]

Input: 17
Output:
[17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49]

Pictorial Presentation:

Sample Solution:

Python Code:

#License: https://bit.ly/3oLErEI

def test(n):    
    return [n + 2 * i for i in range(n)]   
n = 2
print("Number of piles:",n)
print("Number of stones in each pile:")
print(test(n)) 
n = 10
print("\nNumber of piles:",n)
print("Number of stones in each pile:")
print(test(n)) 
n = 3
print("\nNumber of piles:",n)
print("Number of stones in each pile:")
print(test(n)) 
n = 17
print("\nNumber of piles:",n)
print("Number of stones in each pile:")
print(test(n))

Sample Output:

Number of piles: 2
Number of stones in each pile:
[2, 4]

Number of piles: 10
Number of stones in each pile:
[10, 12, 14, 16, 18, 20, 22, 24, 26, 28]

Number of piles: 3
Number of stones in each pile:
[3, 5, 7]

Number of piles: 17
Number of stones in each pile:
[17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39

Flowchart:

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