Python: Check if two lists contain the same elements regardless of order

Python List: Exercise - 257 with Solution

Write a Python program to check if two given lists contain the same elements regardless of order.

• Use set() on the combination of both lists to find the unique values.
• Iterate over them with a for loop comparing the count() of each unique value in each list.
• Return False if the counts do not match for any element, True otherwise.

Sample Solution:

Python Code:

def check_same_contents(nums1, nums2):
  for x in set(nums1 + nums2):
    if nums1.count(x) != nums2.count(x):
      return False
  return True
nums1 = [1, 2, 4]
nums2 = [2, 4, 1]
print("Original list elements:")
print(nums1)
print(nums2)
print("\nCheck two said lists contain the same elements regardless of order!")
print(check_same_contents(nums1, nums2))
nums1 = [1, 2, 3]
nums2 = [1, 2, 3]
print("\nOriginal list elements:")
print(nums1)
print(nums2)
print("\nCheck two said lists contain the same elements regardless of order!")
print(check_same_contents(nums1, nums2))
nums1 = [1, 2, 3]
nums2 = [1, 2, 4]
print("\nOriginal list elements:")
print(nums1)
print(nums2)
print("\nCheck two said lists contain the same elements regardless of order!")
print(check_same_contents(nums1, nums2))

Sample Output:

Original list elements:
[1, 2, 4]
[2, 4, 1]

Check two said lists contain the same elements regardless of order!
True

Original list elements:
[1, 2, 3]
[1, 2, 3]

Check two said lists contain the same elements regardless of order!
True

Original list elements:
[1, 2, 3]
[1, 2, 4]

Check two said lists contain the same elements regardless of order!
False

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