Python: Create a dictionary of keys x, y, and z
Python dictionary: Exercise-40 with Solution
Write a Python program to create a dictionary of keys x, y, and z where each key has as value a list from 11-20, 21-30, and 31-40 respectively. Access the fifth value of each key from the dictionary.
Sample Solution:
Python Code:
from pprint import pprint
dict_nums = dict(x=list(range(11, 20)), y=list(range(21, 30)), z=list(range(31, 40)))
pprint(dict_nums)
print(dict_nums["x"][4])
print(dict_nums["y"][4])
print(dict_nums["z"][4])
for k,v in dict_nums.items():
print(k, "has value", v)
Sample Output:
{'x': [11, 12, 13, 14, 15, 16, 17, 18, 19], 'y': [21, 22, 23, 24, 25, 26, 27, 28, 29], 'z': [31, 32, 33, 34, 35, 36, 37, 38, 39]} 15 25 35 x has value [11, 12, 13, 14, 15, 16, 17, 18, 19] y has value [21, 22, 23, 24, 25, 26, 27, 28, 29] z has value [31, 32, 33, 34, 35, 36, 37, 38, 39]
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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