Python Challenges: Compute and return the square root of a given integer
Python Challenges - 1: Exercise-11 with Solution
Write a Python program to compute and return the square root of a given 'integer'.
Note: The returned value will be an ‘integer’.
Sample Solution:-
Python Code:
def my_sqrt(x):
if x<2: return x
left=1
right=int(x/2)+1
while left<=right:
mid=int((left+right)/2)
if mid*mid==x:
return mid
if mid*mid>x:
right=mid-1
else:
left=mid+1
return right
print(my_sqrt(16))
Sample Output:
4
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Previous: Write a Python program to find three numbers from an array such that the sum of three numbers equal to a given number.
Next: Write a Python program to find the single number in a list that doesn't occur twice.
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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