PHP Challenges: Find majority element in an array
PHP Challenges - 1: Exercise-23 with Solution
Write a PHP program to find majority element in an array.
Input : array(1, 2, 3, 4, 5, 5, 5, 5, 5, 5, 6)
Note: The majority element is the element that appears more than n/2 times where n is the number of elements in the array.
Explanation :
Sample Solution :
PHP Code :
<?php
function majority_element($arr)
{
$idx = 0;
$ctr = 1;
for($i=1; $i<sizeof($arr); $i++)
{
if ($arr[$idx] == $arr[$i])
{
$ctr += 1;
}
else
{
$ctr -= 1;
if ($ctr == 0)
{
$idx = $i;
$ctr = 1;
}
}
}
return $arr[$idx];
}
$num1 = array(1, 2, 3, 4, 5, 5, 5, 5, 5, 5, 6);
$num2 = array(1,2,3,3,3,3,2,3,5,3,1,3,3,4,6,1,3,3,4,6,6);
print_r(majority_element($num1)."\n");
print_r(majority_element($num2)."\n");
?>
Sample Output:
5 3
Flowchart:
PHP Code Editor:
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Previous: Write a PHP program to push all zeros to the end of an array.
Next: Write a PHP program to find the length of the last word in a string.
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PHP: Tips of the Day
How to Sort Multi-dimensional Array by Value?
Try a usort, If you are still on PHP 5.2 or earlier, you'll have to define a sorting function first:
Example:
function sortByOrder($a, $b) { return $a['order'] - $b['order']; } usort($myArray, 'sortByOrder');
Starting in PHP 5.3, you can use an anonymous function:
usort($myArray, function($a, $b) { return $a['order'] - $b['order']; });
And finally with PHP 7 you can use the spaceship operator:
usort($myArray, function($a, $b) { return $a['order'] <=> $b['order']; });
To extend this to multi-dimensional sorting, reference the second/third sorting elements if the first is zero - best explained below. You can also use this for sorting on sub-elements.
usort($myArray, function($a, $b) { $retval = $a['order'] <=> $b['order']; if ($retval == 0) { $retval = $a['suborder'] <=> $b['suborder']; if ($retval == 0) { $retval = $a['details']['subsuborder'] <=> $b['details']['subsuborder']; } } return $retval; });
If you need to retain key associations, use uasort() - see comparison of array sorting functions in the manual
Ref : https://bit.ly/3i77vCC
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