NumPy: replace() function

numpy.core.defchararray.replace() function

For each element in a given array numpy.core.defchararray.replace() function returns a copy of the string with all occurrences of substring old replaced by new.
Calls str.replace element-wise.

Version: 1.15.0

Syntax:

numpy.core.defchararray.replace(a, old, new, count=None)

Parameter:

Return value:

out : ndarray - Output array of str or unicode, depending on input type

Note:

The 'chararray' class exists for backwards compatibility with Numarray, it is not recommended for new development. Starting from numpy 1.4, if one needs arrays of strings, it is recommended to use arrays of 'dtype' 'object_', 'string_' or 'unicode_', and use the free functions in the 'numpy.char' module for fast vectorized string operations.

Some methods will only be available if the corresponding string method is available in your version of Python.

The preferred alias for 'defchararray' is 'numpy.char'.

Example-1: numpy.replace() function

>>> import numpy as np
>>> x = np.char.replace('The quick brown fox', 'fox', 'wolf')
>>> x
array('The quick brown wolf', dtype='<U20')

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Example-2: numpy.replace() function

>>> import numpy as np
>>> x = np.char.replace('The quick fox brown fox', 'fox', 'wolf', count=0)
>>> x
array('The quick fox brown fox', dtype='<U23')

Pictorial Presentation:

Example-3: numpy.replace() function

>>> import numpy as np
>>> x = np.char.replace('The quick fox brown fox', 'fox', 'wolf', count=1)
>>> x
array('The quick wolf brown fox', dtype='<U24')

Pictorial Presentation:

Example-4: numpy.replace() function

>>> import numpy as np
>>> x = np.char.replace('The quick fox brown fox', 'fox', 'wolf', count=2)
>>> x
array('The quick wolf brown wolf', dtype='<U25')

Pictorial Presentation:

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