JavaScript: Check two given integers, whether one is positive and another one is negative

Last update on May 30 2022 09:58:38 (UTC/GMT +8 hours)

JavaScript Basic: Exercise-20 with Solution

Write a JavaScript program to check from two given integers, whether one is positive and another one is negative.

Pictorial Presentation:

JavaScript: Check two given integers, one is positive and one is negative

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>JavaScript program to  check from two given integers, whether one is positive and another one is negative.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function positive_negative(x, y)
{
  if ((x < 0 && y > 0) || x > 0 && y < 0) 
  {
    return true;
  }
  else 
  {
    return false;
  }
}
console.log(positive_negative(2, 2));
console.log(positive_negative(-2, 2));
console.log(positive_negative(2, -2));
console.log(positive_negative(-2, -2));

Sample Output:

false
true
true
false

Flowchart:

ES6 Version:

function positive_negative(x, y)
{
  if ((x < 0 && y > 0) || x > 0 && y < 0) 
  {
    return true;
  }
  else 
  {
    return false;
  }
}
console.log(positive_negative(2, 2));
console.log(positive_negative(-2, 2));
console.log(positive_negative(2, -2));
console.log(positive_negative(-2, -2));

Live Demo:

See the Pen JavaScript: positive negative number: basic-ex-20 by w3resource (@w3resource) on CodePen.

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JavaScript: Tips of the Day

How to insert an item into an array at a specific index (JavaScript)?

What you want is the splice function on the native array object.

arr.splice(index, 0, item); will insert item into arr at the specified index (deleting 0 items first, that is, it's just an insert). In this example we will create an array and add an element to it into index 2:

var arr = []; arr[0] = "Jani"; arr[1] = "Hege"; arr[2] = "Stale"; arr[3] = "Kai Jim"; arr[4] = "Borge"; console.log(arr.join()); arr.splice(2, 0, "Lene"); console.log(arr.join());

Ref: https://bit.ly/2BXbp04