Java String Exercises: Find the second most frequent character in a given string

Java String: Exercise-34 with Solution

Write a Java program to find the second most frequent character in a given string.

Pictorial Presentation:

Sample Solution:

Java Code:

import java.util.*;
public class Main {
 static final int NOOFCHARS = 256;
 static char get2ndMostFreq(String str1) {

  int[] ctr = new int[NOOFCHARS];
  int i;
  for (i = 0; i < str1.length(); i++)
   (ctr[str1.charAt(i)]) ++;

  int ctr_first = 0, ctr_second = 0;
  for (i = 0; i < NOOFCHARS; i++) {
   if (ctr[i] > ctr[ctr_first]) {
    ctr_second = ctr_first;
    ctr_first = i;
   } else if (ctr[i] > ctr[ctr_second] && ctr[i] != ctr[ctr_first])
    ctr_second = i;
  }
  return (char) ctr_second;
 }
 public static void main(String args[]) {
  String str1 = "successes";
  System.out.println("The given string is: " + str1);
  char res = get2ndMostFreq(str1);
  if (res != '\0')
   System.out.println("The second most frequent char in the string is: " + res);
  else
   System.out.println("No second most frequent character found in the string.");
 }
}

Sample Output:

The given string is: successes
The second most frequent char in the string is: c

Flowchart:

Java Code Editor:

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