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Java Exercises: Find the longest increasing continuous subsequence in a given array of integers

Java Basic: Exercise-178 with Solution

Write a Java program to find the longest increasing continuous subsequence in a given array of integers.

Sample Solution:

Java Code:

import java.util.*;
public class Solution {
 public static void main(String[] args) {
  int[] nums = { 10, 11, 12, 13, 14, 7, 8, 9, 1, 2, 3 };
  System.out.println("Original array: " + Arrays.toString(nums));
  System.out.println("Size of longest increasing continuous subsequence: " + longest_seq(nums));
 }

 public static int longest_seq(int[] nums) {
  int max_sequ = 0;
  if (nums.length == 1) return 1;
  for (int i = 0; i < nums.length - 1; i++) {
   int ctr = 1;
   int j = i;
   if (nums[i + 1] > nums[i]) {
    while (j < nums.length - 1 && nums[j + 1] > nums[j]) {
     ctr++;
     j++;
    }
   } else if (nums[i + 1] < nums[i]) {
    while (j < nums.length - 1 && nums[j + 1] < nums[j]) {
     ctr++;
     j++;
    }
   }
   if (ctr > max_sequ) {
    max_sequ = ctr;
   }
   i += ctr - 2;
  }
  return max_sequ;
 }
}

Sample Output:

Original array: [10, 11, 12, 13, 14, 7, 8, 9, 1, 2, 3]
Size of longest increasing continuous subsequence: 5

Pictorial Presentation:

Java exercises: Find the longest increasing continuous subsequence in a given array of integers
Java exercises: Find the longest increasing continuous subsequence in a given array of integers

Flowchart:

Flowchart: Java exercises: Find the longest increasing continuous subsequence in a given array of integers.

Java Code Editor:

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Java: Tips of the Day

How to sort an ArrayList?

Collections.sort(testList);
Collections.reverse(testList);

That will do what you want. Remember to import Collections though!

Ref: https://bit.ly/32urdSe