C++ Exercises: Display such a pattern for n number of rows using number

C++: For Loop Exercise-47 with Solution

Write a program in C++ to display such a pattern for n number of rows using number. Each row will contain odd numbers of number. The first and last number of each row will be 1 and middle column will be the row number.

Sample Solution:-

C++ Code :

#include <iostream>
using namespace std;

int main()
{
   int i,j,n;
    cout << "\n\n Display a pattern using odd number of numbers, the first and last number of each row is 1:\n";
    cout << "-----------------------------------------------------------------------------------------------\n";
    cout << " Input number of rows: ";
    cin >> n;
    for(i=0;i<=n;i++)
   {
     /* print blank spaces */
     for(j=1;j<=n-i;j++)
	cout<<" ";
     /* Display number in ascending order upto middle*/
     for(j=1;j<=i;j++)
       cout<<j;
 
     /* Display  number in reverse order after middle */
       for(j=i-1;j>=1;j--)
	  cout<<j;
     cout<<endl;
   }
} 

Sample Output:

 Display a pattern using odd number of numbers, the first and last number of each row is 1:                                                   
-----------------------------------------------------------------------------------------------                                               
 Input number of rows: 5                                               
                                                                       
    1                                                                  
   121                                                                 
  12321                                                                
 1234321                                                               
123454321 

Flowchart:

C++ Code Editor:

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