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C++ Exercises: Display Pascal's triangle like right angle triangle

C++ For Loop: Exercise-46 with Solution

Write a program in C++ to display Pascal's triangle like right angle triangle.

Sample Solution:-

C++ Code :

#include <iostream>
using namespace std;

int main()
{
    int row,c=1,blk,i,j;
    cout << "\n\n Display the Pascal's triangle lime right angle triangle:\n";
    cout << "-------------------------------------------------------------\n";
    cout << " Input number of rows: ";
    cin >> row;
    for(i=0;i<row;i++)
    {
        for(j=0;j<=i;j++)
        {
            if (j==0||i==0)
                c=1;
            else
               c=c*(i-j+1)/j;
            cout<<c<<"   ";
        }
        cout<<endl;
    }
} 

Sample Output:

 Display the Pascal's triangle lime right angle triangle:              
-------------------------------------------------------------          
 Input number of rows: 7                                               
1                                                                      
1   1                                                                  
1   2   1                                                              
1   3   3   1                                                          
1   4   6   4   1                                                      
1   5   10   10   5   1                                                
1   6   15   20   15   6   1

Flowchart:

Flowchart: Display Pascal's triangle like right angle traingle

C++ Code Editor:

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Next: Write a program in C++ to display such a pattern for n number of rows using number. Each row will contain odd numbers of number. The first and last number of each row will be 1 and middle column will be the row number.

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