C++ Exercises: Check if an array of integers contains a 3 next to a 3 or a 5 next to a 5 or both

C++ Basic Algorithm: Exercise-108 with Solution

Write a C++ program to check if an array of integers contains a 3 next to a 3 or a 5 next to a 5 or both.

Sample Solution:

C++ Code :

#include <iostream>
using namespace std;

static bool test(int nums[], int arr_length)
        {
        for (int i = 0; i < arr_length - 1; i++) if ((nums[i] == 3 && nums[i + 1] == 3) || (nums[i] == 5 && nums[i] == 5)) return true;
     	return false;
          }   
          
int main() 
 {  
  int nums1[] = {5, 5, 5, 5, 5};
  int arr_length = sizeof(nums1) / sizeof(nums1[0]);
  cout << test(nums1, arr_length) << endl; 
  int nums2[] = {1, 2, 3, 4};
  arr_length = sizeof(nums2) / sizeof(nums2[0]);
  cout << test(nums2, arr_length) << endl;
  int nums3[] = {3, 3, 5, 5, 5, 5};
  arr_length = sizeof(nums3) / sizeof(nums3[0]);
  cout << test(nums3, arr_length) << endl;
  int nums4[] = {1, 5, 5, 7, 8, 10};
  arr_length = sizeof(nums4) / sizeof(nums4[0]);
  cout << test(nums4, arr_length) << endl;
  return 0;    
}

Sample Output:

1
0
1
1

Pictorial Presentation:

Flowchart:

C++ Code Editor:

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