C++ Exercises: Check if a given array of integers contains no 3 or a 5

C++ Basic Algorithm: Exercise-107 with Solution

Write a C++ program to check if a given array of integers contains no 3 or a 5.

Sample Solution:

C++ Code :

#include <iostream>
using namespace std;

static bool test(int nums[], int arr_length)
        {
          bool three = false;
          bool five = false;

            for (int i = 0; i < arr_length; i++)
            {
                if (nums[i] == 3) {three = true;}
                if (nums[i] == 5) {five  = true;}
                if (three && five) return false;
            }
            return true;
          }   
          
int main() 
 {  
  int nums1[] = {5, 5, 5, 5, 5};
  int arr_length = sizeof(nums1) / sizeof(nums1[0]);
  cout << test(nums1, arr_length) << endl; 
  int nums2[] = {3, 3, 3, 3};
  arr_length = sizeof(nums2) / sizeof(nums2[0]);
  cout << test(nums2, arr_length) << endl;
  int nums3[] = {3, 3, 3, 5, 5, 5};
  arr_length = sizeof(nums3) / sizeof(nums3[0]);
  cout << test(nums3, arr_length) << endl;
  int nums4[] = {1, 6, 8, 10};
  arr_length = sizeof(nums4) / sizeof(nums4[0]);
  cout << test(nums4, arr_length) << endl;
  return 0;    
}

Sample Output:

1
1
0
1

Pictorial Presentation:

Flowchart:

C++ Code Editor:

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