C Exercises: Perform a binary search in an array
C Variable Type : Exercise-12 with Solution
Write a C program to perform a binary search in an array.
Sample Solution:
C Code:
#include<stdio.h>
#include<stdlib.h>
int compare_integers (const void * x, const void * y)
{
return ( *(int*)x - *(int*)y );
}
int main ()
{
int * arrItem;
int findValue;
int my_array[100];
int n,i;
printf("\nInput the number of elements to be stored in the array :");
scanf("%d",&n);
printf("Input %d elements in the array :\n",n);
for(i=0;i<n;i++)
{
printf("element - %d : ",i+1);
scanf("%d",&my_array[i]);
}
printf (" Input a value to search : ");
scanf ("%d", &findValue);
arrItem = (int*) bsearch (&findValue,
my_array, n, sizeof (int), compare_integers);
if (arrItem != NULL)
printf ("%d is found in the array.\n\n",*arrItem);
else
printf ("%d is not found in the array.\n\n",findValue);
return 0;
}
Sample Output:
Input the number of elements to be stored in the array :5 Input 5 elements in the array : element - 1 : 10 element - 2 : 15 element - 3 : 20 element - 4 : 25 element - 5 : 30 Input a value to search : 20 20 is found in the array.
Flowchart:
C Programming Code Editor:
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Previous: Write a C program to allocate a block of memory for an array.
Next: Write a C program to convert a string to an integer.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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