C Exercises: Allocate a block of memory for an array
C Variable Type : Exercise-11 with Solution
Write a C program to allocate a block of memory for an array.
Sample Solution:
C Code:
#include<stdio.h>
#include<stdlib.h>
int main ()
{
int i,n,num;
int * my_array;
printf("\nInput the number of elements to be stored in the array :");
scanf("%d",&n);
printf("Input %d elements in the array :\n",n);
my_array = (int*) calloc ( n,sizeof(int) );
if (my_array==NULL)
{
printf (" Requested memory allocation is wrong.");
exit (1);
}
for ( i=0; i<n; i++ )
{
printf (" element %d : ",i+1);
scanf ("%d",&my_array[i]);
}
printf (" Values entered in the array are : \n");
for ( i=0; i<n; i++ )
printf (" %d ",my_array[i]);
printf ("\n\n");
free (my_array);
return 0;
}
Sample Output:
Input the number of elements to be stored in the array :5 Input 5 elements in the array : element 1 : 5 element 2 : 10 element 3 : 15 element 4 : 20 element 5 : 25 Values entered in the array are : 5 10 15 20 25
Flowchart:
C Programming Code Editor:
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Next: Write a C program to perform a binary search in an array.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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