C Programming: Count total number of vowel or consonant
C String: Exercise-9 with Solution
Write a program in C to count total number of vowel or consonant in a string.
Sample Solution:
C Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define str_size 100 //Declare the maximum size of the string
void main()
{
char str[str_size];
int i, len, vowel, cons;
printf("\n\nCount total number of vowel or consonant :\n");
printf("----------------------------------------------\n");
printf("Input the string : ");
fgets(str, sizeof str, stdin);
vowel = 0;
cons = 0;
len = strlen(str);
for(i=0; i<len; i++)
{
if(str[i] =='a' || str[i]=='e' || str[i]=='i' || str[i]=='o' || str[i]=='u' || str[i]=='A' || str[i]=='E' || str[i]=='I' || str[i]=='O' || str[i]=='U')
{
vowel++;
}
else if((str[i]>='a' && str[i]<='z') || (str[i]>='A' && str[i]<='Z'))
{
cons++;
}
}
printf("\nThe total number of vowel in the string is : %d\n", vowel);
printf("The total number of consonant in the string is : %d\n\n", cons);
}
Sample Output:
Count total number of vowel or consonant : ---------------------------------------------- Input the string : Welcome to w3resource.com The total number of vowel in the string is : 9 The total number of consonant in the string is : 12
Flowchart:
C Programming Code Editor:
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Next: Write a program in C to find maximum occurring character in a string.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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