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C Programming: Check whether a character is Hexadecimal Digit or not

C String: Exercise-23 with Solution

Write a program in C to check whether a character is Hexadecimal Digit or not.

C Programming: Check whether a character is Hexadecimal Digit or not

Sample Solution:

C Code:

#include<stdio.h>
#include<ctype.h>


int main()
{
	char TestChar;
	printf("\n Check whether a character is Hexadecimal Digit or not :\n");  
    printf("-------------------------------------------------------\n");      
    printf(" Input a character : "); // Hexadecimal Digits are a-f, A-F or 0-9
    scanf( "%c", &TestChar );
	if( isxdigit(TestChar) )
		printf( " The entered character is a hexadecimal digit. \n" );
	else
		printf( " The entered character is not a hexadecimal digit. \n" );
	return 0;
}

Sample Output:

 Check whether a character is Hexadecimal Digit or not :
-------------------------------------------------------
 Input a character : 7
 The entered character is a hexadecimal digit.

Flowchart :

Flowchart: Check whether a character is Hexadecimal Digit or not

C Programming Code Editor:

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP