C Programming: Check whether a given substring is present in the given string
C String: Exercise-14 with Solution
Write a C program to check whether a given substring is present in the given string.
Sample Solution:
C Code:
#include <stdio.h>
void main()
{
char str[80],search[20];
int c1=0,c2=0,i,j,flg;
printf("\n\nCheck whether a given substring is present in the given string :\n");
printf("-------------------------------------------------------------------\n");
printf("Input the string : ");
fgets(str, sizeof str, stdin);
printf("Input the substring to be search : ");
fgets(search, sizeof search, stdin);
while (str[c1]!='\0')
c1++;
c1--;
while (search[c2]!='\0')
c2++;
c2--;
for(i=0;i<=c1-c2;i++)
{
for(j=i;j<i+c2;j++)
{
flg=1;
if (str[j]!=search[j-i])
{
flg=0;
break;
}
}
if (flg==1)
break;
}
if (flg==1)
printf("The substring exists in the string.\n\n");
else
printf("The substring is not exists in the string. \n\n");
}
Sample Output:
Check whether a given substring is present in the given string : ------------------------------------------------------------------- Input the string : This is a test string. Input the substring to be search : search The substring is not exists in the string.
Flowchart :
C Programming Code Editor:
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Next: Write a program in C to read a sentence and replace lowercase characters by uppercase and vice-versa.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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