C Exercises: Hailstone Sequence of a given number upto 1
C Recursion : Exercise-18 with Solution
Write a program in C to find the Hailstone Sequence of a given number upto 1.
Sample Solution:
C Code:
#include <stdio.h>
// function to generate next number
int getNextValue(int aNum)
{
int i = aNum;
if (i % 2 == 0)
{
i = i/2;
}
else
{
i = 3 * i + 1;
}
return (i);// returning the value of next number to the called function
}
// function to generate Hailstone number
void getHailstone(int aNum)
{
int hlSe = aNum;
if (hlSe == 1)
{
printf("%i ", hlSe);
}
else
{
printf(" %i ", hlSe);
getHailstone(getNextValue(hlSe));// calling the function itself recursively
}
}
// Function to count the length of the Hailstone sequence
int countLength(int aNum)
{
int hlSe = aNum;
if(hlSe == 1)
{
return 1;
}
else
{
return 1+countLength(getNextValue(hlSe));// calling the function itself recursively
}
}
int main(int argu)
{
int aNum;
printf("\n\n Recursion : Hailstone Sequence of a given number upto 1 :\n");
printf("--------------------------------------------------------------\n");
printf(" Input any number (positive) to start for Hailstone Sequence : ");
scanf("%i", &aNum);
printf("\n The hailstone sequence starting at %i is : \n", aNum);
getHailstone(aNum);
printf("\n\n");
printf(" The length of the sequence is %i. \n\n", countLength(aNum));
return 0;
}
Sample Output:
Recursion : Hailstone Sequence of a given number upto 1 : -------------------------------------------------------------- Input any number (positive) to start for Hailstone Sequence : 13 The hailstone sequence starting at 13 is : 13 40 20 10 5 16 8 4 2 1 The length of the sequence is 10
Flowchart:
C Programming Code Editor:
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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