C Exercises: Generate mersenne primes within a range of numbers
C Numbers: Exercise-33 with Solution
Write a program in C to generate mersenne primes within a range of numbers.
Test DataInput a upper limit [range from 1 to upper limit]: 1000
Sample Solution:
C Code:
# include <stdio.h>
# include <stdlib.h>
# include <stdbool.h>
# include <math.h>
void GenAllPrim(int n1, bool prarr1[])
{
for (int i=0; i<=n1; i++)
prarr1[i] = true;
for (int p=2; p*p<=n1; p++)
{
if (prarr1[p] == true)
{
for (int i=p*2; i<=n1; i += p)
prarr1[i] = false;
}
}
}
void chkMerPrime(int nm)
{
bool prarr1[nm+1];
GenAllPrim(nm,prarr1);
for (int j=2; ((1<<j)-1) <= nm; j++)
{
long long num = (1<<j) - 1;
if (prarr1[num])
printf(" %lli ",num);
}
}
int main()
{
int n ;
printf("\n\n Generate Mersenne primes within a range of numbers:\n");
printf("--------------------------------------------------------\n");
printf(" Input a upper limit [range from 1 to upper limit]: ");
scanf("%d",&n);
printf(" Mersenne prime numbers are: \n");
chkMerPrime(n);
printf("\n\n");
}
Sample Output:
Input a upper limit [range from 1 to upper limit]: 1000 Mersenne prime numbers are: 3 7 31 127
Pictorial Presentation:
Flowchart:
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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