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C Exercises: Convert a decimal number to hexadecimal

C For Loop: Exercise-55 with Solution

Write a program in C to convert a decimal number to hexadecimal.

Pictorial Presentation:

Convert a decimal number to hexadecimal

Sample Solution:

C Code:

#include <stdio.h>

void main() 
        {
	long int decn,rmd,q,dn=0,m,l;
	int i=1,j,tmp;
        char s;

       printf("\n\nConvert Decimal to Hexadecimal:\n ");
       printf("-------------------------\n");

	printf("Input  any Decimal number: ");
	scanf("%ld",&decn);
	q = decn;
        for(l=q;l>0;l=l/16)
               {
		tmp = l % 16;
		if( tmp < 10)
		           tmp =tmp + 48; else
		         tmp = tmp + 55;
                         dn=dn*100+tmp;
	        }
          printf("\nThe equivalent Hexadecimal Number : ");
         for(m=dn;m>0;m=m/100)
            {
               s=m % 100;
               printf("%c",s);
            }
    printf("\n\n");
}

Sample Output:

Convert Decimal to Hexadecimal:                                                                               
 -------------------------                                                                                    
Input  any Decimal number: 79                                                                                 
                                                                                                              
The equivalent Hexadecimal Number : 4F 

Flowchart:

Flowchart : Convert a number in decimal to hexadecimal

C Programming Code Editor:

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Previous: Write a program in C to convert an octal number into binary.
Next: Write a program in C to Check Whether a Number can be Express as Sum of Two Prime Numbers.

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP