C Exercises: Convert a decimal number to hexadecimal
C For Loop: Exercise-55 with Solution
Write a program in C to convert a decimal number to hexadecimal.
Pictorial Presentation:
Sample Solution:
C Code:
#include <stdio.h>
void main()
{
long int decn,rmd,q,dn=0,m,l;
int i=1,j,tmp;
char s;
printf("\n\nConvert Decimal to Hexadecimal:\n ");
printf("-------------------------\n");
printf("Input any Decimal number: ");
scanf("%ld",&decn);
q = decn;
for(l=q;l>0;l=l/16)
{
tmp = l % 16;
if( tmp < 10)
tmp =tmp + 48; else
tmp = tmp + 55;
dn=dn*100+tmp;
}
printf("\nThe equivalent Hexadecimal Number : ");
for(m=dn;m>0;m=m/100)
{
s=m % 100;
printf("%c",s);
}
printf("\n\n");
}
Sample Output:
Convert Decimal to Hexadecimal: ------------------------- Input any Decimal number: 79 The equivalent Hexadecimal Number : 4F
Flowchart:
C Programming Code Editor:
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Previous: Write a program in C to convert an octal number into binary.
Next: Write a program in C to Check Whether a Number can be Express as Sum of Two Prime Numbers.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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