C Exercises: Determine the LCM of two numbers using HCF

C For Loop: Exercise-44 with Solution

Write a program in C to find LCM of any two numbers using HCF.

Pictorial Presentation:

Sample Solution:

C Code:

#include <stdio.h>

void main()  
{  
    int i, n1, n2, j, hcf=1,lcm;  


     printf("\n\n  LCM of two numbers:\n ");
     printf("----------------------\n");


    printf("Input 1st number for LCM: ");  
    scanf("%d", &n1);  
    printf("Input 2nd number for LCM: ");  
    scanf("%d", &n2); 
  
    j = (n1<n2) ? n1 : n2;  
  
    for(i=1; i<=j; i++)  
    {  

        if(n1%i==0 && n2%i==0)  
        {  
            hcf = i;  
        }  
    }  
/* We know  the multiplication of HCF and LCM is equivalant
to the multiplication of these two numbers.*/
    lcm=(n1*n2)/hcf;
  
    printf("\nThe LCM of %d and %d is : %d\n\n", n1, n2, lcm);  

} 

Sample Output:

  LCM of two numbers:                                                                                         
 ----------------------                                                                                       
Input 1st number for LCM: 15                                                                                  
Input 2nd number for LCM: 20                                                                                  
                                                                                                              
The LCM of 15 and 20 is : 60

Flowchart:

C Programming Code Editor:

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