C Exercises: Calculate the sum of the series [ x - x^3 + x^5 + ......]
C For Loop: Exercise-24 with Solution
Write a program in C to find the sum of the series [ x - x^3 + x^5 + ......].
Sample Solution:
C Code:
#include <stdio.h>
#include <math.h>
void main()
{
int x,sum,ctr;
int i,n,m,mm,nn;
printf("Input the value of x :");
scanf("%d",&x);
printf("Input number of terms : ");
scanf("%d",&n);
sum =x; m=-1;
printf("The values of the series: \n");
printf("%d\n",x);
for (i = 1; i < n; i++)
{
ctr = (2 * i + 1);
mm = pow(x, ctr);
nn = mm * m;
printf("%d \n",nn);
sum = sum + nn;
m = m * (-1);
}
printf("\nThe sum = %d\n",sum);
}
Sample Output:
Input the value of x :2 Input number of terms : 5 The values of the series: 2 -8 32 -128 512 The sum = 410
Flowchart:
C Programming Code Editor:
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Previous: Write a program in C to display the sum of the series [ 1+x+x^2/2!+x^3/3!+....].
Next: Write a program in C to display the n terms of square natural number and their sum.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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