C Exercises: Accepts 4 integers and check various condition
C Basic Declarations and Expressions: Exercise-19 with Solution
Write a C program that accepts 4 integers p, q, r, s from the user where q, r and s are positive and p is even. If q is greater than r and s is greater than p and if the sum of r and s is greater than the sum of p and q print "Correct values", otherwise print "Wrong values".
C Code:
#include <stdio.h>
int main() {
int p, q, r, s;
printf("\nInput the first integer: ");
scanf("%d", &p);
printf("\nInput the second integer: ");
scanf("%d", &q);
printf("\nInput the third integer: ");
scanf("%d", &r);
printf("\nInput the fourth integer: ");
scanf("%d", &s);
if((q > r) && (s > p) && ((r+s) > (p+q)) && (r > 0) && (s > 0) && (p%2 == 0))
{
printf("\nCorrect values\n");
}
else {
printf("\nWrong values\n");
}
return 0;
}
Flowchart:
Sample Output:
Input the first integer: 25 Input the second integer: 35 Input the third integer: 15 Input the fourth integer: 46 Wrong values
C Programming Code Editor:
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Next: Write a C program to print the roots of Bhaskara’s formula from the given three floating numbers. Display a message if it is not possible to find the roots.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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