C Exercises: Convert a given integer to years, months and days

C Basic Declarations and Expressions: Exercise-18 with Solution

Write a C program to convert a given integer (in days) to years, months and days, assumes that all months have 30 days and all years have 365 days.

C Code:

#include <stdio.h>
int main() {
	int ndays, y, m, d;	
	
	printf("Input no. of days: ");
	
	scanf("%d", &ndays);
	
	y = (int) ndays/365;
	
	ndays = ndays-(365*y);
		
	m = (int)ndays/30;
	
	d = (int)ndays-(m*30);
	
	printf(" %d Year(s) \n %d Month(s) \n %d Day(s)", y, m, d);
	return 0;
}

Sample Output:

Input no. of days: 2535                                                
 6 Year(s)                                                             
 11 Month(s)                                                           
 15 Day(s)

Flowchart:

C Programming Code Editor:

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