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C Exercises: Find the element(s) which occurs most frequently in a given sequence

C Basic Declarations and Expressions: Exercise-140 with Solution

Write a C program to which reads a sequence of integers and find the element which occurs most frequently.

Sample Solution:

C Code:

#include <stdio.h>
#include<stdlib.h>
#include<math.h>
#include<string.h>
int main(void) {
  int in ;
  int nums[101] = {0};
  int i;
  int max_val = 0;
  printf("\nInput the terms of the sequence:\n");
  while (scanf("%d", & in ) != EOF)
    nums[ in ]++;

  for (i = 1; i <= 100; i++) {
    if (max_val < nums[i])
      max_val = nums[i];
  }
  printf("Mode values of the said sequence in ascending order:\n");
  for (i = 1; i <= 100; i++) {
    if (max_val == nums[i])
      printf("%d\n", i);
  }
  return 0;
}

Sample Output:

Input the terms of the sequence:
5
2
4
6
8
10
^Z
Mode values of the said sequence in ascending order:
2
4
5
6
8
10

Flowchart:

C Programming Flowchart: Find the element(s) which occurs most frequently in a given sequence.

C programming Code Editor:

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Previous: Write a C program to find the maximum sum of a contiguous subsequence from a given sequence of numbers a1, a2, a3, ... an ( n = number of terms in the sequence).
Next: Write a C program that reads n digits (given) chosen from 0 to 9 and prints the number of combinations where the sum of the digits equals to another given number (s). Do not use the same digits in a combination.

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP