C Exercises: Maximum sum of a contiguous subsequence from a given sequence of numbers
C Basic Declarations and Expressions: Exercise-139 with Solution
Write a C program to find the maximum sum of a contiguous subsequence from a given sequence of numbers a1, a2, a3, ... an ( n = number of terms in the sequence).
You can assume that 1 <= n <= 500 and -10000 <= ai <= 10000.
A contiguous subsequence of a list S is a subsequence made up of consecutive elements of S.
For instance, if S is
5, 15, −30, 10, −5, 40, 10,
then 15, −30, 10 is a contiguous subsequence but 5, 15, 40 is not.
Give a linear-time algorithm for the following task:
• Input: A list of numbers a1, a2, . . . , an
• Output: The contiguous subsequence of maximum sum. (Note that a subsequence of
length zero has sum zero.)
For the preceding example, the answer would be 10, −5, 40, 10, with a sum of 55
Ref: https://bit.ly/2IGGI3f
Sample Solution:
C Code:
#include <stdio.h>
int main() {
int n;
long a[5000];
long long max, tmp;
int i, j;
printf("Input number of terms in the sequence:\n");
scanf("%d", & n);
printf("\nInput the terms of the said sequence:\n");
for (i = 0; i < n; i++) scanf("%ld", & (a[i]));
max = a[0];
tmp = 0;
for (i = 0; i < n; i++) {
for (j = i; j < n; j++) {
tmp += a[j];
if (max < tmp)
max = tmp;
}
tmp = 0;
}
printf("Maximum sum of a contiguous subsequence:\n");
printf("%lld\n", max);
return 0;
}
Sample Output:
Input number of terms in the sequence: 5 Input the terms of the said sequence: 3 2 6 -7 8 Maximum sum of a contiguous subsequence: 12
Flowchart:
C programming Code Editor:
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Previous: Write a C program to test whether two lines are parallel or not. The four points are P(x1, y1), Q(x2, y2), R(x3, y3) and S(x4, y4), check PQ and RS are parallel are not.
Next: Write a C program to which reads a sequence of integers and find the element which occurs most frequently.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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