C Exercises: Create a new array after replacing all the values 5 with 0 shifting all zeros to right direction

C-programming basic algorithm: Exercise-72 with Solution

Write a C program to create a new array after replacing all the values 5 with 0 shifting all zeros to right direction.

C Code:

#include <stdio.h>
#include <stdlib.h>
int main(void){ 
    int arr_size;
    int a1[] = {1, 2, 0, 3, 5, 7, 0, 9, 11, 5};
    arr_size = sizeof(a1)/sizeof(a1[0]);
    printf("Elements in original array are: ");  
    print_array(a1, arr_size);    
     int size = arr_size, index = 0;
     int result[size];
            for (int i = 0; i < size; i++)
            {
                if (a1[i] != 5)
                {
                    result[index++] = a1[i];
                }
            }
    arr_size = sizeof(result)/sizeof(result[0]);                
    printf("\nElements in new array are: ");  
    print_array(result, arr_size);
    }       
 print_array(int parray[], int size)
  {
   int i;      
   for( i=0; i<size-1; i++)  
    {  
        printf("%d, ", parray[i]);  
    } 
   printf("%d ", parray[i]);  
   printf("\n");   
  }

Sample Output:

Elements in original array are: 1, 2, 0, 3, 5, 7, 0, 9, 11, 5 

Elements in new array are: 1, 2, 0, 3, 7, 0, 9, 11, 0, 0

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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