C Exercises: Create a new array from a given array of integers shifting all zeros to left direction
C-programming basic algorithm: Exercise-71 with Solution
Write a C program to create a new array from a given array of integers shifting all zeros to left direction.
C Code:
#include <stdio.h>
#include <stdlib.h>
int main(void){
int arr_size;
int a1[] = {1, 2, 0, 3, 5, 7, 0, 9, 11};
arr_size = sizeof(a1)/sizeof(a1[0]);
printf("Elements in original array are: ");
print_array(a1, arr_size);
int pos = 0;
for (int i = 0; i < arr_size; i++)
{
if (a1[i] == 0)
{
a1[i] = a1[pos];
a1[pos++] = 0;
}
}
arr_size = sizeof(a1)/sizeof(a1[0]);
printf("\nElements in new array are: ");
print_array(a1, arr_size);
}
print_array(int parray[], int size)
{
int i;
for( i=0; i<size-1; i++)
{
printf("%d, ", parray[i]);
}
printf("%d ", parray[i]);
printf("\n");
}
Sample Output:
Elements in original array are: 1, 2, 0, 3, 5, 7, 0, 9, 11 Elements in new array are: 0, 0, 1, 3, 5, 7, 2, 9, 11
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Flowchart:
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Next: Write a C program to create a new array after replacing all the values 5 with 0 shifting all zeros to right direction.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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