C Exercises: Check a given array of integers of length 3 and create a new array
C-programming basic algorithm: Exercise-44 with Solution
Write a C program to check a given array of integers of length 3 and create a new array. If there is a 5 in the given array immediately followed by a 7 then set 7 to 1.
C Code:
#include <stdio.h>
#include <stdlib.h>
int main(void){
int arr_size;
int array1[] = {1, 5, 7};
arr_size = sizeof(array1)/sizeof(array1[0]);
printf("Elements in original array are: ");
print_array(array1, arr_size);
for (int i = 0; i < arr_size - 1; i++)
{
if (array1[i] == 5 && array1[i + 1] == 7)
array1[i + 1] = 1;
}
printf("Elements in new array are: ");
print_array(array1, arr_size);
}
print_array(int parray[], int size)
{
int i;
for( i=0; i<size-1; i++)
{
printf("%d, ", parray[i]);
}
printf("%d ", parray[i]);
printf("\n");
}
Sample Output:
Elements in original array are: 1, 5, 7 Elements in new array are: 1, 5, 1
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Flowchart:
C Programming Code Editor:
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Previous: Write a C program to check a given array of integers and return true if the array conains 10 or 20 twice.The length of the array will be 0, 1, or 2.
Next: Write a C program to compute the sum of the two given arrays of integers of length 3 and find the array which has the largest sum.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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