C Exercises: Check a given array of integers and return true if the array contains 10 or 20 twice

C-programming basic algorithm: Exercise-43 with Solution

Write a C program to check a given array of integers and return true if the array contains 10 or 20 twice. The length of the array will be 0, 1, or 2.

C Code:

#include <stdio.h>
#include <stdlib.h>
int main(void){
    int arr_size;
    int array1[] = {12, 20};
    arr_size = sizeof(array1)/sizeof(array1[0]);
    printf("%d",test(array1, arr_size));
    int array2[] = {20, 20};
    arr_size = sizeof(array2)/sizeof(array2[0]);
    printf("\n%d",test(array2, arr_size));
    int array3[] =  {10};
    arr_size = sizeof(array3)/sizeof(array3[0]);
    printf("\n%d",test(array3, arr_size));
    }       
    int test(int nums[], int size)
         {
             return size == 2
                && ((nums[0] == 10 && nums[1] == 10)
                     || (nums[0] == 20 && nums[1] == 20));
        }

Sample Output:

0
1
0

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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