SQL Subquery Exercises: Find all those customers who hold a different grade than any customer of the city Dallas
SQL SUBQUERY : Exercise-30 with Solution
30. From the following tables write a SQL query to find all those customers who have different grades than any customer who lives in Dallas City. Return customer_id, cust_name,city, grade and salesman_id.
Sample table: Customer
Sample Solution:
SELECT *
FROM customer
WHERE NOT grade = ANY
(SELECT grade
FROM customer
WHERE city='Dallas');
Output of the Query:
customer_id cust_name city grade salesman_id 3002 Nick Rimando New York 100 5001 3007 Brad Davis New York 200 5001 3005 Graham Zusi California 200 5002 3008 Julian Green London 300 5002 3004 Fabian Johnson Paris 300 5006 3009 Geoff Cameron Berlin 100 5003 3003 Jozy Altidor Moscow 200 5007 3001 Brad Guzan London 5005
Pictorial Presentation:
Practice Online
Query Visualization:
Duration:
Rows:
Cost:
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Previous: From the following tables, write a SQL query to find those customers whose grade are not same of those customers living in Paris. Return customer_id, cust_name, city, grade and salesman_id.
Next: From the following tables, write a SQL query to find the average price of each manufacturer's product along with their name. Return Average Price and Company.
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SQL: Tips of the Day
SQL Server SELECT into existing table.
INSERT INTO dbo.TABLETWO SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:
INSERT INTO dbo.TABLETWO (col1, col2) SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
Database: SQL Server
Ref: https://bit.ly/3y6tpA3
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