SQL Subquery Exercises: Find all orders with order amounts which are on or above-average amounts for their customers

SQL SUBQUERY : Exercise-13 with Solution

13. From the following tables write a SQL query to find those orders that are equal or higher than the average amount of the orders. Return ord_no, purch_amt, ord_date, customer_id and salesman_id.

Sample table: Orders

Sample table: Customer

Sample Solution:

SELECT * 
FROM orders a
WHERE purch_amt >=
    (SELECT AVG(purch_amt) FROM orders b 
     WHERE b.customer_id = a.customer_id);

Output of the Query:

ord_no	purch_amt	ord_date	customer_id	salesman_id
70009	270.65		2012-09-10	3001		5005
70005	2400.60		2012-07-27	3007		5001
70008	5760.00		2012-09-10	3002		5001
70010	1983.43		2012-10-10	3004		5006
70003	2480.40		2012-10-10	3009		5003
70011	75.29		2012-08-17	3003		5007
70013	3045.60		2012-04-25	3002		5001
70007	948.50		2012-09-10	3005		5002
70012	250.45		2012-06-27	3008		5002

Explanation:

Practice Online

Query Visualization:

Duration:

Rows:

Cost:

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Previous: From the following tables, write a SQL query to find those orders, which are higher than average amount of the orders. Return ord_no, purch_amt, ord_date, customer_id and salesman_id.
Next: Write a query to find the sums of the amounts from the orders table, grouped by date, eliminating all those dates where the sum was not at least 1000.00 above the maximum order amount for that date.