SQL Subquery Exercises: Display all the customers with orders issued on date 17th August, 2012
SQL SUBQUERY: Exercise-10 with Solution
10. From the following tables write SQL query to find the customers who placed orders on 17th August 2012. Return ord_no, purch_amt, ord_date, customer_id, salesman_id and cust_name.
Sample table: Orders
Sample table: Customer
Sample Solution:
SELECT b.*, a.cust_name
FROM orders b, customer a
WHERE a.customer_id=b.customer_id
AND b.ord_date='2012-08-17';
Output of the Query:
ord_no purch_amt ord_date customer_id salesman_id cust_name 70004 110.50 2012-08-17 3009 5003 Geoff Cameron 70011 75.29 2012-08-17 3003 5007 Jozy Altidor
Explanation:
Practice Online
Query Visualization:
Duration:
Rows:
Cost:
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Previous: From the following tables, write a SQL query to find those salespeople who earned the maximum commission. Return ord_no, purch_amt, ord_date, and salesman_id.
Next: From the following tables, write a SQL query to find the salespeople who had more than one customer. Return salesman_id and name.
What is the difficulty level of this exercise?
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SQL: Tips of the Day
SQL Server SELECT into existing table.
INSERT INTO dbo.TABLETWO SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:
INSERT INTO dbo.TABLETWO (col1, col2) SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
Database: SQL Server
Ref: https://bit.ly/3y6tpA3
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